4[1-(4x-3)]=7(4-2x)

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Solution for 4[1-(4x-3)]=7(4-2x) equation:


Simplifying
4[1 + -1(4x + -3)] = 7(4 + -2x)

Reorder the terms:
4[1 + -1(-3 + 4x)] = 7(4 + -2x)
4[1 + (-3 * -1 + 4x * -1)] = 7(4 + -2x)
4[1 + (3 + -4x)] = 7(4 + -2x)

Combine like terms: 1 + 3 = 4
4[4 + -4x] = 7(4 + -2x)
[4 * 4 + -4x * 4] = 7(4 + -2x)
[16 + -16x] = 7(4 + -2x)
16 + -16x = (4 * 7 + -2x * 7)
16 + -16x = (28 + -14x)

Solving
16 + -16x = 28 + -14x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '14x' to each side of the equation.
16 + -16x + 14x = 28 + -14x + 14x

Combine like terms: -16x + 14x = -2x
16 + -2x = 28 + -14x + 14x

Combine like terms: -14x + 14x = 0
16 + -2x = 28 + 0
16 + -2x = 28

Add '-16' to each side of the equation.
16 + -16 + -2x = 28 + -16

Combine like terms: 16 + -16 = 0
0 + -2x = 28 + -16
-2x = 28 + -16

Combine like terms: 28 + -16 = 12
-2x = 12

Divide each side by '-2'.
x = -6

Simplifying
x = -6

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